Circles (tangents, chords, arcs, sectors, angle properties)-Math SPM

Circles (tangents, chords, arcs, sectors, angle properties)-Math SPM

Circles (tangents, chords, arcs, sectors, angle properties)-Math SPM

Circles (Tangents, Chords, Arcs, Sectors, Angle Properties) – Complete Guide with Examples

Understanding Circles: Tangents, Chords, Arcs, Sectors, and Angle Properties

A circle is a fundamental geometric shape consisting of all the points in a plane that are equidistant from a fixed center point. In geometry, learning about parts of a circle—including tangents, chords, arcs, sectors, and angle properties—is essential for understanding complex figures, solving real-world problems, and preparing for standardized exams.

Tangents

A tangent is a line that touches the circle at exactly one point and is perpendicular to the radius at the point of contact.

Easy Questions

1. Find the length of a tangent from a point 5 cm away from the center of a circle with a radius of 3 cm.
**Solution:**
Using Pythagoras:
$$ \text{Tangent}^2 = 5^2 – 3^2 = 25 – 9 = 16 $$
$$ \text{Tangent} = \sqrt{16} = 4\ \text{cm} $$

2. True or False: A tangent intersects the circle at two points.
**Solution:**
False. A tangent touches the circle at exactly one point.

Medium Questions

1. A tangent from an external point forms an angle of \(60^\circ\) with a radius. Find the triangle area formed by the tangent, the radius, and the line to the center.
**Solution:**
Use trigonometry to find area:
$$ A = \frac{1}{2} r \cdot t \cdot \sin(60^\circ) = \frac{1}{2} \cdot r \cdot r \cdot \sqrt{3}/2 = \frac{r^2 \sqrt{3}}{4} $$

2. Two tangents are drawn from a point outside the circle and the angle between them is \(70^\circ\). What is the angle at the center between the radii?
**Solution:**
Use the isosceles triangle rule:
$$ \text{Angle at center} = 180^\circ – 70^\circ = 110^\circ $$

Hard Questions

1. Find the length of the tangent from point P to a circle if the radius is 6 cm and the distance from P to the center is 10 cm.
**Solution:**
$$ t^2 = 10^2 – 6^2 = 100 – 36 = 64 \Rightarrow t = 8\ \text{cm} $$

2. Prove that tangents drawn from an external point are equal.
**Solution:**
Use triangle congruence:
\( \angle OTP = \angle OTP’ \), radii are equal, and OP = OP’. By RHS rule, triangles are congruent \( \Rightarrow PT = PT’ \)

Chords

A chord is a line segment that connects two points on a circle. A diameter is the longest possible chord.

Easy Questions

1. What is the longest chord in a circle of radius 7 cm?
**Solution:**
Diameter = \(2 \times 7 = 14\ \text{cm}\)

2. True or False: Every diameter is a chord.
**Solution:**
True.

Medium Questions

1. In a circle of radius 5 cm, find the distance from the center to a chord of length 8 cm.
**Solution:**
Use Pythagorean Theorem in a right triangle:
$$ \left(\frac{8}{2}\right)^2 + d^2 = 5^2 \Rightarrow 16 + d^2 = 25 \Rightarrow d = 3\ \text{cm} $$

2. Two chords of equal length are 4 cm long in a circle. Prove they are equidistant from the center.
**Solution:**
Equal chords in a circle are equidistant from the center by the converse of circle theorems.

Hard Questions

1. Prove the perpendicular from the center of a circle to a chord bisects the chord.
**Solution:**
Use triangle congruence (RHS) to prove each half is equal.

2. A chord is 12 cm long and is 5 cm from the center. Find the radius.
**Solution:**
$$ (6)^2 + 5^2 = r^2 \Rightarrow r^2 = 36 + 25 = 61 \Rightarrow r = \sqrt{61} $$

Arcs

An arc is any portion of the circumference of a circle defined by two endpoints.

Easy Questions

1. What is a semicircle’s arc length in a circle of radius 4 cm?
**Solution:**
$$ \frac{1}{2} \cdot 2\pi r = \pi r = \pi \cdot 4 = 4\pi\ \text{cm} $$

2. True or False: An arc smaller than a semicircle is called a major arc.
**Solution:**
False. It is a minor arc.

Medium Questions

1. In a circle of radius 6 cm, find the arc length subtended by a central angle \(60^\circ\).
**Solution:**
$$ \text{Arc length} = \frac{60^\circ}{360^\circ} \cdot 2\pi \cdot 6 = \frac{1}{6} \cdot 12\pi = 2\pi\ \text{cm} $$

2. Calculate the angle at the center that subtends an arc of length \(5\pi\) cm in a circle of radius 10 cm.
**Solution:**
$$ \theta = \frac{5\pi \cdot 180^\circ}{\pi \cdot 10} = \frac{900}{10} = 90^\circ $$

Hard Questions

1. Prove that equal arcs subtend equal angles at the center.
**Solution:**
Use proportionality of arc length and equal radii to show equal angular displacement.

2. A minor arc has length 3.14 cm in a circle with radius 5 cm. Find central angle \( \theta \) in degrees.
**Solution:**
$$ \theta = \frac{3.14 \cdot 180}{\pi \cdot 5} = \frac{565.2}{15.7} \approx 36^\circ $$

Sectors

A sector is a region bounded by two radii and the included arc.

Easy Questions

1. What fraction of the circle is a quarter circle?
**Solution:**
$$ \frac{90^\circ}{360^\circ} = \frac{1}{4} $$

2. True or False: The area of a semicircular sector is half the area of the circle.
**Solution:**
True.

Medium Questions

1. Find the sector area for a radius of 7 cm and a central angle of \(60^\circ\).
**Solution:**
$$ A = \frac{60^\circ}{360^\circ} \cdot \pi r^2 = \frac{1}{6} \cdot \pi \cdot 49 = \frac{49\pi}{6}\ \text{cm}^2 $$

2. What is the perimeter of a \(90^\circ\) sector of a circle with radius 4 cm?
**Solution:**
$$ \text{Arc length} = \frac{90}{360} \cdot 2\pi \cdot 4 = 2\pi $$
$$ \text{Perimeter} = 2\pi + 4 + 4 = 2\pi + 8 $$

Hard Questions

1. A sector has area \(100\pi\ \text{cm}^2\) and central angle \(60^\circ\). Find the radius.
**Solution:**
$$ \frac{60}{360} \cdot \pi r^2 = 100\pi \Rightarrow \frac{1}{6} r^2 = 100 \Rightarrow r^2 = 600 \Rightarrow r = \sqrt{600} \approx 24.49\ \text{cm} $$

2. Find angle θ of a sector with area \(24\pi\) and radius 6 cm.
**Solution:**
$$ \frac{\theta}{360} \cdot \pi \cdot 6^2 = 24\pi $$
$$ \frac{36\theta}{360} = 24 \Rightarrow \theta = 240^\circ $$

Angle Properties

Angle properties of circles include theorems about angles in the same segment, angles at the center vs circumference, and cyclic quadrilaterals.

Easy Questions

1. True or False: Angle subtended by a diameter = 90°.
**Solution:**
True.

2. What is the angle at the center if the angle at circumference is 40°?
**Solution:**
$$ \angle \text{Center} = 2 \times 40^\circ = 80^\circ $$

Medium Questions

1. Find missing angle: Triangle inscribed in a circle has two angles 60° and 70°.
**Solution:**
Third angle = 180° – (60° + 70°) = 50°

2. In a cyclic quadrilateral, one angle is 110°. Find opposite angle.
**Solution:**
Opposite = 180° – 110° = 70°

Hard Questions

1. Prove that the angle subtended by the same arc at the circumference is equal.
**Solution:**
Use angle at center theorem and subtract appropriately to show equality.

2. Find angle at center subtending a chord whose angle at circumference is \(45^\circ\)
**Solution:**
Center angle = \(2 \times 45^\circ = 90^\circ\)

Why Study Circles?

Studying circles helps in mastering spatial reasoning, geometric proofs, engineering design, architecture, satellite communication, and more. Recent studies on circle geometry and its applications include work by Maryam Mirzakhani, who explored hyperbolic geometry and moduli spaces involving circular topologies.

Researchers in analytic geometry and topology continue building on century-old geometrical theorems with computational modeling and real-world applications.

Join Skorminda Today!

Want to master circles and other advanced math topics? Join Skorminda today and benefit from expert-led classes, interactive examples, and custom learning paths tailored to each student’s pace and understanding. Whether preparing for exams or enhancing skill, Skorminda is your perfect math companion!

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